sample

for node 40
Sa=6133.4
Sb=1596.8
St=886.8
Code stress from CII=7930.9

asumming Ia=1.0
SL= (Ia(Sa+Sb)2+(2St)2)1/2
SL=7930.9 = code stress from CII

but for node 25
Sa=5338.3
Sb=5851.1
St=554.6
Code Stress from CII=9789.6

SL= (Ia(Sa+Sb)2+(2St)2)1/2
assuming Ia=1.0 (or whichever is greater than 0.75SIFo, from CII help box)
SL=11443.3
thus SL computed manually is greater than from code stress from CII.
strange answer, because i think Ia=1.0 is the least value of COde stress of sustained stress..

Please clarify.thanks