Hi Experts,
I need a piece of information, please.



Input data are:

Vertical pipe from node 10 (lower node) to node 20 (upper node);

Distance between node 10 and node 20 (pipe length): 1000mm;

Pipe diameter, thickness and material: 1"-STD schedule-A106B
(but is not relevant for this example);

Reference system: X axis and Z axis are horizontal, Y axis is vertical;

Restraints at node 10 only: Guide (along X and Z) and Y (this Y is the restraint, not vertical axis);

Imposed displacement at node 20 only: 1000mm along X axis (other displacements and rotations are left blank);

Installation and working temperature are the same (21.1111°C).



Displacements report:

CASE 1 (OPE) W+D1

Node 10
DX 0.000mm
DY 0.000mm
DZ 0.000mm
RX 0.000deg
RY 0.000deg
RZ -57.296deg


Node 20
DX 1000.000mm
DY 0.000mm
DZ 0.000mm
RX 0.000deg
RY 0.000deg
RZ -57.296deg


So, RZ at node 20 is 57.296deg therefore DX is not a linear displacement but is the length of a circumference arc (OK, even if I think that the displacement I imposed was horizontal);

DY at node 20 is zero!!!

Please, can You explain me why DY at node 20 is zero?
I think that it should be -158.527mm if I consider that RZ!

Thanks.
Best regards.


Edited by Alessiaccio (11/05/15 11:11 AM)
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