Example given...
T= 100°F || 200°F
---------------------------
S= 20.0 kpsi || 15.0 kpsi
To find S at 150°F, CAESAR II would use linear interpolation and arrive at 17.5 kpsi
However the code may give the following data because test data showed a slightly non-linear behavior between 100 and 200°F.
T= 100°F || 150°F || 200°F
-------------------------------------
S= 20.0 kpsi || 17.7 kpsi || 15.0 kpsi
_________________________
Steve Perry