Mariog,

I will send you the papers today. Regarding my post, this is how I could get 1=2 well at least nearly.

Since k= 1.4 ,the expression for PX A that I got earlier can be written as :

= W x 0.71 X SQRT( k x R' X Texit)

The expression in my post is :

(W x 1.88/g) X SQRT( k x g XR' X Texit)

This is equal to :

((W X 1.88 )/ SQRT(g)) X SQRT( kxg XR'XTexit)

Since g=9.81m/sec^2 and inverse of SQRT g= 0.319, the above expression comes to :

WX1.88X0.319 X SQRT( kx R'XTexit) = W x 0.6 X SQRT( kx R'XTexit)

Hope my algebra above was correct.

Regards