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#920 - 02/20/03 09:35 AM Specifying Eccentric reducers
Ajay Kumar Offline
Member

Registered: 01/31/03
Posts: 2
Loc: Chennai , India
Hi,
How to specify eccentric reducer in CAESARII . It is explained in the application guide but it gives a good picture about concentric one .
In my case i have to specify one eccentric reducer for the vertical run of pipe .
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Ajay Kumar

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#921 - 02/20/03 09:59 AM Re: Specifying Eccentric reducers
Richard Ay Offline
Member

Registered: 12/13/99
Posts: 6226
Loc: Houston, Texas, USA
Assuming you are going to use "average properties", here is an example of a concentric reducer model and an eccentric reducer model.

Concentric Model:
D1 = 8.625 t1 = 0.322 L = 16.0
D2 = 6.625 t2 = 0.280

In CAESAR II -> DX = 16, Diam=7.625 Thck=.301

Eccentric Model:
D1 = 8.625 t1 = 0.322 L = 16.0
D2 = 6.625 t2 = 0.280

In CAESAR II -> DX = 16, DY=-1.00
Diam=7.625 Thck=.301
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Richard Ay - Consultant

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#922 - 02/24/03 09:17 AM Re: Specifying Eccentric reducers
Gustavo Cuervo Offline
Member

Registered: 01/30/03
Posts: 5
I want to add that when you specify an eccentric reduction (or concentric too) you have to use SIF’S=2 (the maximum, or use the equation, Applications guide page 6-2) in the node when the reduction starts and in the node when the reduction ends (each end of the reducer element).

Regards

Gustavo Cuervo
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Gustavo Cuervo

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#923 - 03/19/03 01:55 PM Re: Specifying Eccentric reducers
Samuel Offline
Member

Registered: 10/21/02
Posts: 8
Loc: Edmonton, Canada
For Eccentric: why not DY = (6.625-8.625)/2 = -1.0? (a half of delta OD rather than a half of Delta thickness)
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SL

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#924 - 03/19/03 02:11 PM Re: Specifying Eccentric reducers
Richard Ay Offline
Member

Registered: 12/13/99
Posts: 6226
Loc: Houston, Texas, USA
Oops, you're 100% correct. I'll fix the above post.
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Richard Ay - Consultant

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#925 - 03/19/03 04:01 PM Re: Specifying Eccentric reducers
Andrew Weighell Offline
Member

Registered: 01/15/00
Posts: 52
Loc: England, UK
I've always assumed that the average properties model is complicated for little, if any, improvement of accuracy(?).
A 50% big / 50% small model is probably adequate and within the relatively wide modelling tolerances. More importantly, it has the advantage of correctly reporting the stress at the small end? I came across a calc recently where the the small end didn't show an overstress with notional average properties but was overstressed with correct properties !!!! ?

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#926 - 03/26/03 09:49 AM Re: Specifying Eccentric reducers
Amit Offline
Member

Registered: 03/25/03
Posts: 8
Loc: Mumbai
For either type of Reducer, is it required to put Tapered Transition? I want to understand the significant effect CAESER shows by selecting this option.
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Amit Paradkar

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#927 - 04/02/03 02:34 PM Re: Specifying Eccentric reducers
Edward Klein Offline
Member

Registered: 10/24/00
Posts: 334
Loc: Houston, Texas, USA
Just a reminder, B31.3 does not apply an SIF to reducers the way B31.1 does.

I would also like to get some clarification on the "tapered transition" fitting type. I've seen other people use it in a file to model the two ends of a reducer, but I don't know what the basis for that is and there's no mention that I can find in the manuals as to what it is supposed to mean. I was admittedly disturbed to see it generate an SIF value at all in a B31.3 model, if it is intended to represent a reducer.
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Edward L. Klein
Pipe Stress Engineer

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