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#72778 - 01/31/19 10:15 AM force by pressure only
vermaccio Offline
Member

Registered: 09/05/17
Posts: 169
Loc: italy
i have a pipe (external diameter 212.2mm, thickness 3.8mm) and
so:
Pipe radius R=(212.2-3.8-3.8)/2=102.3mm=10.23cm

Pressure: 1bar.

I modeled a spool 1000mm lenght, anchor at both sides.
Material A106B, B31.3

Load case: only "P1" OPE because i want to read only force due to pressure.

By hand calculus:
P=F/S so i want calculate F=P*S

P= pressure inside pipe= 1bar=10N/cm2
S= area inside pipe = pi*R^2 = 3.14*(10.23)^2 = 328cm2

so i should have a force on both pipe sides (on both anchors) equal to:
F=P*S=3280N

BUT...
if i make this calculs by caesar i obtain on anchors 1368N only.

Where is the mistake? why caesar does't give me the real force due to pressure on anchors?

maybe i am too tired to see an incredible mistake in my hand calculus?

thank you

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#72780 - 01/31/19 11:43 AM Re: force by pressure only [Re: vermaccio]
Dorin Daniel Popescu Offline
Member

Registered: 06/05/00
Posts: 151
Loc: Middle East
Have you activated Bourdon Effect ("translation only") from Environment / Special Execution menu?

In my opinion, this option MUST ALWAYS be activated foe anr pressurized pipe.

Regards,
_________________________
Dorin Daniel Popescu

Lead Piping Stress Engineer

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#72781 - 02/01/19 01:16 AM Re: force by pressure only [Re: Dorin Daniel Popescu]
vermaccio Offline
Member

Registered: 09/05/17
Posts: 169
Loc: italy
yes, already active. i still don't understand why i don't obtain tghe right pressure-force on anchors at pipe sides.... frown frown

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#72782 - 02/01/19 02:48 AM Re: force by pressure only [Re: vermaccio]
danb Offline
Member

Registered: 04/22/05
Posts: 1453
Loc: ...
Please consider that you are not in the situation when an expansion joint is between two anchors.
If you do not use Bourdon effect you will have 0 force on the anchors. If you activate Bourdon you will have some but not full thrust. The pipe has not a discontinuity, so will tend to contain the pressure.

Regards,
_________________________
Dan

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#72783 - 02/01/19 06:35 AM Re: force by pressure only [Re: vermaccio]
anubis512 Offline
Member

Registered: 08/24/18
Posts: 118
Loc: USA
The force you calculated is based on the internal area of the pipe; wouldn't this require the pipe to be capped & anchored at both ends to be accurate? In real life the pipe doesn't know the anchor is there to exert pressure on that internal face. I don't think an anchor attached to the outside of your pipe would see force of the same magnitude.

I don't think Bourdon is necessary for all pressurized pipe, unless you believe you have elongation/ovalization or particularly high pressure.

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#72784 - 02/01/19 07:23 AM Re: force by pressure only [Re: vermaccio]
engineer001ch Offline
Member

Registered: 12/21/18
Posts: 28
Loc: China
I think in your case anchor load should be less than P*S
I found this explanation http://www.whatispiping.com/restrained-and-unrestrained1

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#72785 - 02/01/19 09:16 AM Re: force by pressure only [Re: engineer001ch]
vermaccio Offline
Member

Registered: 09/05/17
Posts: 169
Loc: italy
thank you smile

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