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#69044 - 05/19/17 07:13 AM Bi-linear restraints in burried piping
innovation Offline
Member

Registered: 03/27/14
Posts: 6
Loc: india
Hey friends,

Please help me to understand the functioning of bi-linear restraints used in burried piping. I will be thankful if you guide me on following.

•For buried piping how axial stiffness K1 & axial yield or ultimate
force Fy values are calculated

•I understand that lateral stiffness values K1 & lateral yield or
ultimate force Fy must be as per L.C Peng’s papers on underground
piping published in April/May 1978.

•C-II shows two stiffness K1 & K2. Here K2 is always 1 whereas K1
seems to be calculated as per Peng's paper. Now how stiffness K1 &
K2 are considered in the analysis. I mean when K1 is used & when K2
is used? Please elaborate how it is applied in the analysis.

Thanks for your time.

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#69046 - 05/19/17 09:21 AM Re: Bi-linear restraints in burried piping [Re: innovation]
Richard Ay Offline
Member

Registered: 12/13/99
Posts: 6226
Loc: Houston, Texas, USA
From the User's Guide:

Quote:
Soil supports are modeled as bi-linear springs having an initial stiffness, an ultimate load, and a yield stiffness. The yield stiffness is typically set close to zero. After the ultimate load on the soil is reached, there is no further increase in load even though the displacement may continue.


A restraint starts off with the stiffness of K1. Once the ultimate load is reached, the stiffness is switched from K1 to K2. (Numerically you can't have a zero stiffness, so we use 1.0 for K2.)
_________________________
Regards,
Richard Ay - Consultant

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