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#61639 - 12/30/14 02:03 AM water hammer static calculation
tqd_stress_analysis Offline
Member

Registered: 03/12/14
Posts: 74
Loc: Italy
Hi all,

I need to simulate a static water hammer phenomenon in my model (code is EN 13480); my questions are:

-There is any simplified formula to calculate a equivalent force

I initially used this F=DLF*DeltaP*Ai

where
DLF= dynami load factor=3
deltaP= pressure difference
Ai=internal area of the pipe


-Where to apply this calculated force? (each 90 degree bend after the valve or even on 45 degree bend too?)

TY.

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#61644 - 12/30/14 07:29 AM Re: water hammer static calculation [Re: tqd_stress_analysis]
Pablo_GH Offline
Member

Registered: 05/18/13
Posts: 52
Loc: Spain
Dear,

You are correct. As usual, F=m*a=P*A=ro*L*A*(dv/dt). Adding as you has done, the DLF.

Remember (you can find more in this forum):
Originally Posted By: Dave Diehl
DLF has max of 2.0 for a single application of an impulse load.


In water hammer there are several constants you have to know or calculate to obtain the deltaP, such as density, element lenght, valve closure time, fluid velocity, ... You can look for the Joukowsky equation and read the theory.

You can find more information about water hammer formulas and theory reading Chaudhry (1987), Fox (1989), Hwang and Houghtalen (1996), and Wylie and Streeter (1978).

Regards.

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#61646 - 12/30/14 09:57 AM Re: water hammer static calculation [Re: tqd_stress_analysis]
tqd_stress_analysis Offline
Member

Registered: 03/12/14
Posts: 74
Loc: Italy
Ty Pablo.

Someone have any example of this calculations?

And the other question is: at which point should be applied this calculated force?

Maybe a pratical example can be useful; probably I will find it on the articles cited above.


Edited by tqd_stress_analysis (12/30/14 09:58 AM)

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