Dear,
You are correct. As usual, F=m*a=P*A=ro*L*A*(dv/dt). Adding as you has done, the DLF.
Remember (you can find more in this forum):
DLF has max of 2.0 for a single application of an impulse load.
In water hammer there are several constants you have to know or calculate to obtain the deltaP, such as density, element lenght, valve closure time, fluid velocity, ... You can look for the Joukowsky equation and read the theory.
You can find more information about water hammer formulas and theory reading Chaudhry (1987), Fox (1989), Hwang and Houghtalen (1996), and Wylie and Streeter (1978).
Regards.