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#4438 - 12/21/05 08:13 PM About stress report of C2
Twing Offline
Member

Registered: 05/11/05
Posts: 50
Loc: China
smile The stress report as following:
........
3180 37451. 9161. 1.000 / 1.000 41748. 248590. 17.
3180 37451. -9161. 1.000 / 1.000 41748. 248590. 17.
3188 42011. 9161. 1.000 / 1.000 45888. 256533. 18.
3188 98971. -9161. 2.356 / 2.356 108028. 255633. 42.
3189 45789. 21883. 2.356 / 2.356 112948. 249251. 45.
3189 45789. -21883. 2.356 / 2.356 112948. 249251. 45.
3190 34466. 22892. 2.356 / 2.356 113473. 245912. 46.
3190 14630. -22892. 1.000 / 1.000 48307. 250636. 19.
3200 14456. 22892. 1.000 / 1.000 48255. 250638. 19.
3200 20942. -22892. 1.449 / 1.449 69797. 250104. 28.
........
From 3188 to 3190,this element is a elbow,and the SIF is only acting on the 3188 and 3190.But for the same point(refer to 3188&3190),they have the different SIF.How can we consider this?And Which code stress should we select as the actual code stress?
_________________________
Regards!
WangXuDong

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#4439 - 12/21/05 09:39 PM Re: About stress report of C2
whm Offline
Member

Registered: 08/29/05
Posts: 101
Loc: China
Dear twing,

3188 42011. 9161. 1.000 / 1.000 45888. 256533. 18.
3188 98971. -9161. 2.356 / 2.356 108028. 255633. 42.

You find that one node(3188) have two different SIF:1 and 2.356,right?

Ok, this is not a problem,one SIF is for the straight pipe 3180-3188, another SIF is for the
elbow

Hope that can help you!
_________________________
whmwhm

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#4440 - 03/04/06 09:28 PM Re: About stress report of C2
Twing Offline
Member

Registered: 05/11/05
Posts: 50
Loc: China
Dear whm.
Thanks for your reply.
_________________________
Regards!
WangXuDong

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#4441 - 03/05/06 10:46 AM Re: About stress report of C2
Richard Ay Offline
Member

Registered: 12/13/99
Posts: 6226
Loc: Houston, Texas, USA
when reviewing the "force" or "stress" reports, the elements are reported - sort of like a "free body diagram". For example:

line 1) data for node 10 on element A
line 2) data for node 20 on element A
blank line
line 3) data for node 20 on element B
line 4) data for node 30 on element B
blank line
line 5) data for node 30 on element C
line 6) data for node 40 on element C

So node 20 is reported twice, because it belongs to two different elments. The same is true for node 30. Now, if node 30 happens to be a tee, then there will be a third element someplace else in the report with the data for node 30 for this 3rd element.

Since each element can have its own cross-section data, the force and the stress report can show very different data for the same node as you move from element to element.
_________________________
Regards,
Richard Ay - Consultant

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