HelLo Everybody,

As given in WRC 297 the width of the reinforcing pad or insert plate shall be at least 1.65*sqrt(rt) to consider its effect as a reinforcement & again to sustain the external loads.

But as you said that at a distance sqrt(rt) the stresses due to external loads will be die.

So, why the factor 1.65 is given in the WRC? Alos is this necessary to consider the factor 1.65 or the width can be only sqrt(rt)?

In some cases where we are using the self reinforced nozzles the hub outside diameter is much more & then again the width as per WRC 297 leads to increase the inert plate diameter to a very big dimension.

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Regards,

Makrand Sakpal

Contact No: - 9967949656