Dear friends
I am not very experienced in caesar.i would like to learn how to model an eccentric reducer in caesar 5.1. This might sound as a silly question. Please help!

thanks

CAESAR II doesn't have a eccentric reducer element, because the Piping Codes don't address this fitting. If you model a reducer, CAESAR II will treat it as a concentric reducer.

To get your geometry correct, just specify the proper delta combintation (say DX and DY) necessary to move between the node points of the reducer.

Here's a quick example:
Running in the X direction with an 8 x 6 inch "flat top" reducer, the centerline of the exiting 6 inch pipe will be 1 inch above the centerline of the 8 inch pipe. The change in position between the From Node and To Node will be - DX:(length of reducer) DY:1

Thank you very much for the reply. you have cleared my doubt.

Cheers

Modelling is one part.
Stress calculation another part.
What for a stress factor do you use for this eccentric reducer ?

In my opinion, the higher SIFs value the more conservation at the point which are evaluated. So I think SIFs value maybe 2 or higher for eccentric reducer.

Is there any idea from others ?

Best regards.