Dear all,

In the below cases, how i evaluated by using Caesar Max Method

CASE TYPE Method
U1+U2+U3 SUS ALG
U1+U2-U3 SUS ALG
U1-U2+U3 SUS ALG
U1-U2-U3 SUS ALG
Thanks,

Assuming you had this:

L1 = U1+U2+U3 SUS ALG
L2 = U1+U2-U3 SUS ALG
L3 = U1-U2+U3 SUS ALG
L4 = U1-U2-U3 SUS ALG

then you could do this:

L5 = L1, L2, L3, L4 SUS MAX

Thanks richard Ay

In my combination i considered

Assume L10=w+p1+ max of above case.

how i include that cases and which is max of above the case.

No, you can't do that. The idea of the "MAX" case is to report the maximum of the listed cases. You can't do any further combintations using the "MAX" case.

L1 = U1+U2+U3 SUS ALG
L2 = U1+U2-U3 SUS ALG
L3 = U1-U2+U3 SUS ALG
L4 = U1-U2-U3 SUS ALG
L5 = L1, L2, L3, L4 SUS MAX
L6 = W + P1
L7 = L5 + L6

Jane,

Your case (7) can yield misleading results depending on the combination method and "what gets computed" versus "what gets directly summed". Your suggestion may work, but only because cases 1 - 4 are uniform loads and don't have a weight or pressure component.

Just be really, really careful with this.

In CAESAR II, basic load cases must be computed before combinations.

I suggest replacing:

L1 = U1+U2+U3 SUS ALG
L2 = U1+U2-U3 SUS ALG
L3 = U1-U2+U3 SUS ALG
L4 = U1-U2-U3 SUS ALG
L5 = L1, L2, L3, L4 SUS MAX
L6 = W + P1
L7 = L5 + L6

with:

L1 = U1+U2+U3 (OCC) ALG
L2 = U1+U2-U3 (OCC) ALG
L3 = U1-U2+U3 (OCC) ALG
L4 = U1-U2-U3 (OCC) ALG
L5 = W+P1 (SUS) ALG
L6 = L1, L2, L3, L4 (OCC) MAX
L7 = L5 + L6 (OCC)

I've also changed those SUS loads to OCC loads. Perhaps those aren't occasional loads but if they are, they should be so noted.

And what about the -U1 permutations?

hai dave diehl & richard
Its case for loyd's comments, my cases only for sustain.
i follow case L7 = L5 + L6.
thanks richard and dave.

lesson learned. =)
thanks richard and dave.

Dear all,

wht is difference between alg, abs and max. explain in brief?
i go through coade help, i can't understand.
why we using that method? what purpose of using that case?

Take two numbers, 125 and -218, then:

An algebraic combination would yield (125 + -218) = -93 )
An absolute combination would yield ( abs(125) + abs(-218) = 343 )
A max combination would yield (-218)
A signed max combination would yield (125)
A signed min combination would yield (-218)