Could be a solution using a proportion beetwen areas of 45degree and 90degree branch connection?
I explain this concept: geometrically 45 degree branch connection area is 1.41 times bigger then 90 degree branch connection area.So the radius of 45 degree branch connection area is bigger then 90 degree branch connection area.
No. If area (moment of inertia) is bigger than SIF must be smaller. FEM modeling confirm It.
When we analysed results of branch FEM shell modeling we discovered that SIF for 45 degree branch is smaller than for 90 degree branch.
But the stress concentration factor (peak stress) in real life is much greater in 45 degree connection than in 90 degree branch. It confirmed by experements. Look WRC 360 (by E.C. Rodabaugh) for example.
i=K*C
K - stress concentration factor. Much greater for 45 degree
C - peak stress from FEM modelling. Lesser for 45 degree
Inplane SIF increase very insignificantly for 45 degree (because moment of inertia is increasing too and C decresing), but outplane SIF increase significantly (moment of inertia become the same, but K is increasing).