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#13067 - 09/08/07 11:04 AM How to calculate displacement vectors?
Noman Offline
Member

Registered: 09/08/07
Posts: 2
Loc: UK
How to calculate displacement vectors?

For example If you look at help>online documents> Application guide> Tutorial A

At nozzle number 5 the deflections are DX = 0, DY = 0.077, DZ = 0.046
At nozzle number 40 the deflections are DX = 0, DY = 0.28, DZ = -0.100

This deflection comes up due to thermal growth at 600 F or 315.55 C.
B31.1 2001 gives us linear growth in different metals at different temperature changes.
Therefore if the nozzle 5 and 40 under goes linear thermal growth at 600F 0r 315.55 C it will grow 3.9 mm/m approximately.

How can one find the direction vectors DX, DY, DZ etc.

Please advise me.

Please explain a bit how to best set boundary conditions.

Thanks,


Noman

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#13071 - 09/09/07 07:47 AM Re: How to calculate displacement vectors? [Re: Noman]
stress river Offline
Member

Registered: 01/23/06
Posts: 81
Loc: china
Noman
I think if you need make a vector decomposition.
so you can set the displacement number in sheet.

for boundary condition, it depand on your project's fact.
I think it is either a anchor setting or a anchor with displacement ,
it should be a simple setting. but you must conside any detail factor.
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#13088 - 09/10/07 10:29 AM Re: How to calculate displacement vectors? [Re: stress river]
Noman Offline
Member

Registered: 09/08/07
Posts: 2
Loc: UK
Thanks for your advise brother but read my quesion
Dear fellow,

At 315.55 C the pipe may grow 3.9 mm/m approximately could be in y direction in case of pump discharge nozzle no 5. But how do you decompose into vectors or if say how COADE decompose this situation into vectors DY and DZ.

I am very puzzle please help me out of it.

By the way thank for boundary conditions again my means was towards setting the displacements.

Many thanks,

Noman

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#13089 - 09/10/07 12:43 PM Re: How to calculate displacement vectors? [Re: Noman]
Richard Ay Offline
Member

Registered: 12/13/99
Posts: 6226
Loc: Houston, Texas, USA
If the displacement is in the "Y" direction, there wouldn't be any component in either the "X" or "Z" directions.

Now if your line is skewed, then the growth would be along that (skewed) line and it would have components in two (or perhaps) three global directions. This is basic trigonometry. The direction cosines are basically the normalized "delta coordinates".
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Richard Ay - Consultant

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