Topic Options
#10063 - 03/05/07 07:22 AM Earthquake analysis
Willem Offline
Member

Registered: 04/15/02
Posts: 3
Loc: South Africa
Is it possible and/or practical to do a earthquake analysis on a buried pipeline with Caesar?


Edited by Willem (03/05/07 07:26 AM)
_________________________
Regards
Willem de Klerk

Top
#10065 - 03/05/07 08:32 AM Re: Earthquake analysis [Re: Willem]
Richard Ay Offline
Member

Registered: 12/13/99
Posts: 6226
Loc: Houston, Texas, USA
Possible - yes. Practical - probably not.

Seismic loads enter a piping system through its supports. The load comes from the inertia of the piping system trying to follow the moving supports. Buried pipe is continuously supported so it will not “see” these inertial loads. The only flaw in this line of thinking is that if the pipe crosses a fault, where the soil shears, you're in trouble.

One other point to consider is that the buried lines will experience the pressure wave as it travels through the soil – and not only at fault lines. (An analogy would be a rope floating on the water where the water waves deflect the rope.) The soil waves are compression and extension (like sound waves) rather than the transverse waves of the water surface but the point is the same. Those deflections could pull the pipe apart. If you had the deflections, CAESAR II might give it a go but this might not be a valid approach.
_________________________
Regards,
Richard Ay - Consultant

Top
#10188 - 03/11/07 12:15 AM Re: Earthquake analysis [Re: Richard Ay]
baburao patil Offline
Member

Registered: 04/25/04
Posts: 13
Loc: Mumbai
Richard,

One thing is not clear to me from your response.You have mentioned that the buried pipe will not be subjected to intertial loading as it is continuously supported.

My question is , from Newton's second law of motion, intertia force is equal to mass times absolute acceleration. In case of a buried pipe , which is continuously supported, the only way the intertia force can be zero is by the absolute acceleration to be zero. Why the absolute acceleration will be zero and how this absolute acceleration changes w.r.t whether the line is supported continuously like buried pipe or intermittently like above ground pipes?

With best regards
_________________________
Barurao Vikasrao Patil

Top
#10192 - 03/11/07 02:52 PM Re: Earthquake analysis [Re: baburao patil]
Richard Ay Offline
Member

Registered: 12/13/99
Posts: 6226
Loc: Houston, Texas, USA
The reason the pipe won't see the typical inertial loads (typical compared to above ground piping) is because in a buried system, the pipe moves with the ground, just as the supports do.
_________________________
Regards,
Richard Ay - Consultant

Top
#10197 - 03/11/07 08:50 PM Re: Earthquake analysis [Re: Richard Ay]
anindya stress Offline
Member

Registered: 04/12/04
Posts: 493
Loc: London, UK
Baburao,

You're right, Inertia force is mass times absolute accelaration.

Now what is this absolute acceleration? It is the sum of two components:

Acceleration relative to ground + Acceleration of ground.

You must be knowing that for engineering analysis, the Newtonian Frame of reference is the one fixed to earth ( although that was not the original Newtonian frame which was "fixed to sun" and not "earth"), hence the absolute acceleration is zero.

Regards
_________________________
anindya

Top
#10573 - 04/05/07 07:21 AM Re: Earthquake analysis [Re: anindya stress]
anindya stress Offline
Member

Registered: 04/12/04
Posts: 493
Loc: London, UK
_________________________
anindya

Top
#10581 - 04/05/07 10:19 AM Re: Earthquake analysis [Re: anindya stress]
CraigB Offline
Member

Registered: 05/16/06
Posts: 378
Loc: Denver, CO
Let's try to explain this from another viewpoint.

For above-ground piping systems, the supports are placed 20-50 pipe diameters apart. This gives a formula for the natural frequency of a straight pipe between two supports of the form f = K/(2 * pi) * sqrt (E*I*g/(w*L^4)). As the span between supports gets longer, the natural frequency decreases. As the natural frequency decreases, the amplitude of the displacement envelope increases. As the amplitude of the displacement envelope increases, the stresses induced by the vibration increase.

Agreed?

OK, now for buried pipe the distance between supports is infinitely small. What, exactly, do you think will happen to the displacements and stresses?

As Richard notes above, there are obviously direct interactions between the soil and buried pipe. However, these are on a scale where local FEA is necessary - CAESAR II is not really valid for local effects.

So I would not recommend trying to solve this problem using CAESAR II. For the effects for which CAESAR II is valid, the stresses are by definition very small. For effects which may cause significant stresses, CAESAR II is not valid.
_________________________
CraigB

Top



Moderator:  Denny_Thomas, uribejl 
Who's Online
0 registered (), 53 Guests and 3 Spiders online.
Key: Admin, Global Mod, Mod
April
Su M Tu W Th F Sa
1 2 3 4 5 6
7 8 9 10 11 12 13
14 15 16 17 18 19 20
21 22 23 24 25 26 27
28 29 30
Forum Stats
12065 Members
14 Forums
16973 Topics
75151 Posts

Max Online: 303 @ 01/28/20 11:58 PM
Top Posters (30 Days)