Posted by: Van Ha
Check the serve cyclic condition - 06/01/18 12:09 PM
Assuming that I have two nodes as follows:
Node 10
LC1 with SE1_10 = Max displacement stress range
LC2 with SE2_10
LC3 with SE3_10
-> Use equation (1d) B31.3 to check if N_10 > 7000
-> Calculate f=6*(N_10)^-0.2
-> Reset SA_10
-> Check if SE1_10 < 0.8*SA_10 then Non-serve cyclic condition
=================================================================
Node 20
LC1 with SE1_20
LC2 with SE2_20 = Max displacement stress range
LC3 with SE3_20
-> Use equation (1d) B31.3 to check if N_20 > 7000
-> Calculate f=6*(N_20)^-0.2
-> Reset SA_20
-> Check if SE2_20 < 0.8*SA_20 then Non-serve cyclic condition
My questions:
1. Since the ratio Si/SE in equation (1d) B31.3 vary from LC to LC and from node to node, should I need to check serve cyclic condition for all nodes in my calculation like above approach (for node 10, 20, etc.) by using Excel?
2. Any other more simple approach by using CII direCtly rather than post-processing with Excel?
Node 10
LC1 with SE1_10 = Max displacement stress range
LC2 with SE2_10
LC3 with SE3_10
-> Use equation (1d) B31.3 to check if N_10 > 7000
-> Calculate f=6*(N_10)^-0.2
-> Reset SA_10
-> Check if SE1_10 < 0.8*SA_10 then Non-serve cyclic condition
=================================================================
Node 20
LC1 with SE1_20
LC2 with SE2_20 = Max displacement stress range
LC3 with SE3_20
-> Use equation (1d) B31.3 to check if N_20 > 7000
-> Calculate f=6*(N_20)^-0.2
-> Reset SA_20
-> Check if SE2_20 < 0.8*SA_20 then Non-serve cyclic condition
My questions:
1. Since the ratio Si/SE in equation (1d) B31.3 vary from LC to LC and from node to node, should I need to check serve cyclic condition for all nodes in my calculation like above approach (for node 10, 20, etc.) by using Excel?
2. Any other more simple approach by using CII direCtly rather than post-processing with Excel?