skewed restraint?

How do you specify a skewed restraint? The users guide describes typing "vecx, vecy, vecz" and C2 will automatically figure out the cosine. I tried manually typing and an error message appeared "Invalid type".

In the field where you would normally specify an "X restraint", type in something like:

X(0.707, 0.0, 0.707)

which will give you a restraint at 45 deg in the horizontal plane. Change the numeric values above to suite the actual direction of your restraint. The "X" label doesn't really matter once you specify the direction cosines.

Thanks Richard,

Typed in x(-.707,0,.707) as only a restraint in the -x direction was needed. But restraints in both directions were placed in the model. How do can a single restraint be obtained?

Are you sure that two restraints were placed in the model?
The output would show both FX and FZ reaction for a single, skewed, restraint. The load should show that FX=FZ since you put the restraint on a 45. The deflection, too, should show that relationship: DX=DZ.

Now, you also say the restraint is in the "-X" direction. You should show that negative sign in your restraint definition (e.g. +X(-.707,0,.707)). If the restraint is "active" in the load case you are looking at, what I said above is true. If the support is inactive, you will have no restraint load and no predefined relation between DX & DZ.