When inserting a 1/2" od x .065" wall nozzle into a shell wall(.140"), using ASME section VIII div 1 figure UW16.1 (W-1). This figure isn't in your popup fields so I leave it blank. Because of this figure,(W-1),I don't use area 1 and 2 in the reinforcement cal's. The weld size of 1/8" pass with this information, as far as all three of the failure paths requirements.
If I don't turn off areas 1 and 2, the weld size of 1/4" is required to pass all of the all three of the failure paths requirements.
Note the requirement of the ASME code states that the nozzle material can't be counted in the reinforcement cal's. I assumed because of the exterior weld was the only support for the nozzle, this would be the only reinforcement that would count towards Total area available, so that is why I turned off areas 1 and 2. This also seems to effect the all three of the failure paths requirements.
Is this the true intent of your program to work this way, or have I miss the boat on the issue.

Marc,

The ASME requirement for w-1 type weld is that the no area contribution should be taken from the nozzle wall. So, you need to set only the Area A2 to zero. The available area comes from the contribution from the shell and the interior weld. The weld strength calculations are dependent on the available area, hence they also change as A2 is set to zero.

You had mentioned that there is an exterior weld, but in the figure W-1 there is only the interior weld. The requirements for the case with exterior weld are different. You may check that !.

Regards,
Mandeep Singh
COADE, Inc.

Thanks for the info.
I forgot to mention that I was using Interpretation VIII-1-92-170 which allows the interior weld shown on figure (W-1) to be an exterior weld. Does this effect your answer?

Ok, that is fine. The response still stays the same: setting only area in nozzle neck (A2) to zero.

Regards,
Mandeep