Hi,

Somebody could explain me if Caesar include or not the thrust forces in elbows, tees, etc. If not, what is the reason why.

I have read a lot of threads here, but I can not understand it altogether

I know that the force is taken by wall of the pipe. But I have an anchor just before a 90° elbow, the pipe is 24" sch 80 and P is 1700 psi, so I Think that this force must be taken by the anchor in this case, so it must include it as a Force or it is already included?

Could help me please.

Dear Sir,

The longitudinal pressure thrust (Pt = P x A) develops at every change in direction of your pipe. Therefore Pt will develop at your upstream elbow / tee but then there will be an equal but opposite Pt at the downstream elbow / tee. The load is transmitted down the pipe in tension, for positive pressure systems, and they cancel each other so that there is no Pt load on your anchors.

In your case, the 721,746# pressure thrust load develops at the up & downstream elbows/tees and will be resisted by tension in the pipe line. At your anchor, you will have a Pt load on the right but then an equal but opposite load on the left so that they cancel and yield no axial pressure load on the anchor.

The only time you need to consider Pt is when you are using an unrestrained expansion joint which is like putting a spring in the middle of your pipe.

Dear Dan....

Many thanks for your answer...

Dear dan,

Maybe I'm explaining wrong, I got 2 anchors, between these blocks exist an elbow LR 70° in plant (horizontal). these are buried.

please see the picture attached in this link:
http://subefotos.com/ver/?9badfa3a865d34a56c023b0d6756dd71o.jpg


Exist a resultant force in the elbow as the picture, but I don't know if Caesar include it automaticly or I must include it manually, or I don't need includ it....

Thanks

You don't need to enter it. The pressure thrust force cancels out with equal and opposite forces at the other end of your pipe.

OK...

Many many thanks!!