Chakot..
I can't precisely say whether this method is 100% accurate but I tried to figure out a way to do so.
Let your three lines be A, B & C with node nos range as 10-100(for A); 100-200 (for B ) & 200-300 (for C). I've presumed that the pipe is uninsulated.
Now the only way I see I can do the above requirements in one file is: by varying the insulation thickness & density.
Calculate a hypothetical cylinder of dia same as ins thickness which will have the same volume as the original pipe of inside dia di.
By calculation & solving the quadratic equation, we get 2di=do where do is outer dia.
Therefore equivalent ins thichness will be t=0.5 di (since t= 0.5 {do-di) )
For operating condtion 1 :
Put fluid densities as 0 for all A,B & C.
Put ins thk as 0.5di for A with condensate density as ins density & for B & C use 0 ins thk & density.
For operating condtion 2 :
Put fluid densities as 0 for all A,B & C.
Put ins thk as 0.5di for A & B with condensate density as ins density for Both A & B
& for C use 0 ins thk & density.
For hydro, you may create a new file.
I know this method may not be fully correct as you've mentioned deletion of insulation (and I've presumed uninsulated pipe) in your post but still thought of giving my brain some feed to solve this Piping puzzle..!!!
You know "An empty mind is a devil's workshop" & being a god-fearing man, I dislike the devil & his workshop
....