Hello Stressers I have a question.
How to implement in CII a restraint which will be not a anchor point
but we need to leave free only one from 6 degrees of freedom.
The best example of this kind of support is restraint from ASME B31.3 Code Example 3.

We have:
Blocked Y - bi-dierection
Blocked Z - bi-dierection
Blocked X - in (minus direction)
And blocked all RX RY and RZ

I asked because we need to do this 6 cells for typing the values but allowable are only 4 ?????

Regards
____________________________________________

Adrian

You can enter the remaining two restraints on other element on previous or next element.Just put the node no which you desire there. Till the node no you intend to use is correct, your results will be correct.

It's typically better to put restraints for a node on elements that share that node number, to facilitate finding that restraint later if you need to change it.

E.G. if your model is 10-20-30, and your support location is 20, place 3 or 4 on 10-20 and the remaining on 20-30.

However, I'll note that double-clicking on the support geometry (e.g. 3d arrow) will automatically bring you to the appropriate element, though when you combine multiple restraint types at the same location, the geometry overlaps (depending which version of CAESAR you use).

Thanks Guys for quick and helpfull answer

CAESAR II 2018 (coming out soon) will provide the entry of 6 restraint vectors on the element input screen

Thank You Dave for information it is great news.

I hope that the material base will be enriched about materials acc. EN Standards that we wrote a few months ago.

I have one more question !
Time to time I have a system with double rod hanger support
it is difference in CII if I make a rod hanger or if I simulate a double rod hanger with beam, shoe and two rods ???

I don't think modeling both rods adds much value. But it will be up to you to qualify the rod diameters for their proper loads.
One issue that comes to mind - if you rigidly attach you supporting beam to your pipe run and provide Y restraints on each end of that beam, you will now have a support couple that will carry a bending moment. That bending moment will alter the even split of the deadweight load between the two supports. One support may actually hold the beam down (with the modeled restraint in compression). So then you might use +Y restraints for this beam and things just get more complicated.
A model simplification with a little more user intervention is the way I would go.